Can someone tell me if I did this correctly? I was to locate absolute extrema of the function on the closed interval.
h(x)=-x^2+3x-5 [-2,1]

Question

Can someone tell me if I did this correctly? I was to locate absolute extrema of the function on the closed interval.
h(x)=-x^2+3x-5                       [-2,1]

anonymous · Answer

If I differentiate it would be h'(x)= -2x+3 
Then setting equal to zero would be x=3/2 which is a critical number
Then, I evaluated at -2,1 and 3/2 and found that the minimum would be -15 and the maximum would be -1/2

anonymous · Answer

Perfect

anonymous · Answer

thank you so much. I felt like i was missing something thats why i was making sure