Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

An object is thrown upward at time t=0. After t seconds, its height is y=−4.9t2+7t+1 meters above the ground. What is the acceleration due to gravity?

OpenStudy (anonymous):

If you've taken any physics course, you know the acceleration due to gravity is 9.8 m/s^2. However, if we want to show this mathematically, then we can find the second derivative of the function, which yields acceleration: height y = -4.9t^2 + 7t + 1 velocity y' = -9.8t + 7 acceleration y'' = -9.8 m/s^2

OpenStudy (anonymous):

ah ok, ty and havent taken physics yet. next semester

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!