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Mathematics 11 Online
OpenStudy (anonymous):

Help please http://prntscr.com/1226g3

OpenStudy (anonymous):

i have solve a and b i need help with part c

OpenStudy (anonymous):

for "c" , we are looking for "t" just like in (b) but negative

OpenStudy (anonymous):

so \[h = -1=7\cos\left({\pi\over3}t\right)\\ t={3\over\pi}\cos^{-1}(-1/7)=? \]

OpenStudy (anonymous):

93.7

OpenStudy (anonymous):

no. I got 1.64s

OpenStudy (dan815):

-1=7cos(3t/pi) t=1.79 secs

OpenStudy (dan815):

well + or - 1.79 but time has to be positive

OpenStudy (dan815):

for your case

OpenStudy (anonymous):

and it says for the "second time". So, to that, you add the comeplete period

OpenStudy (anonymous):

now, the period of oscillation for this is : \[T={3\over2}=1.5s\]

OpenStudy (dan815):

-3=7cos(3t/pi) t=2.1087

OpenStudy (anonymous):

iam getting more confused for -1? -3? -5?

OpenStudy (anonymous):

1) h=-1 \(t=1.5+\displaystyle{3\over\pi}\cos^{-1}(-1/7)=?\)

OpenStudy (dan815):

-5=7cos(3t/pi) 2.478

OpenStudy (anonymous):

iam getting 95

OpenStudy (dan815):

change your calculator to radians

OpenStudy (anonymous):

3.13

OpenStudy (anonymous):

3.42 for -3

OpenStudy (anonymous):

3.75 for -5

OpenStudy (anonymous):

are they correct

OpenStudy (anonymous):

\[ h=-1\qquad t=1.5+\displaystyle{3\over\pi}\cos^{-1}(-1/7)=3.13s\\ h=-3\qquad t=1.5+\displaystyle{3\over\pi}\cos^{-1}(-3/7)=3.42s\\ h=-5\qquad t=1.5+\displaystyle{3\over\pi}\cos^{-1}(-5/7)=3.76s \] so, yes. they are correct

OpenStudy (anonymous):

also, remember that these times can be obtained when the weight is coming from extreme to rest position and from rest to extreme. These times are from mean to extreme

OpenStudy (anonymous):

the values you got for part (b) are from extreme to mean. to get to 1cm, it takes more time than to go to 5cm from rest position!!!

OpenStudy (dan815):

dont use any of my answers i solve for the equation 3/pi x not pi/3 x

OpenStudy (anonymous):

part b's solution is wrrong

OpenStudy (dan815):

what are your answers for part b?

OpenStudy (anonymous):

no. it is correct. I am giving you the interpretation. Look at the time values.

OpenStudy (dan815):

is it 1.36 for the first one

OpenStudy (anonymous):

it tell you that you reach 5cm mark before you reach the 1cm mark. i.e., you are coming from the extreme point to the rest point

OpenStudy (dan815):

1.36,1.08,0.74 ish?

OpenStudy (anonymous):

ok thanks can you confirm my other question

OpenStudy (anonymous):

I do not see a series there in the picture

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

http://prntscr.com/1229cf

OpenStudy (anonymous):

all correct here

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