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oooohh... arithmetic sequence ^.^
Yes :<
first, see if you can find what's called the common difference d... it's what you get if you subtract the first term from the second c'mon now... ^_^
And then? :))
and then..? what's d?
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3
\[\Huge S_n=\frac{n}{2}[2a_1+(n-1)d]\] N=Total terms \(a_1\)=First term d=Common difference here is 24-21=3 --------------------------------- We have to find the total number of terms, we can find that by using the last term, 72, \[T_n=a_1+(n-1)(d)=72 \\ \\ 21+(n-1)(3)=72 \\ \\ n=18\] Substitute in and find the sum
And now, you also have to find n, the number of terms in your sequence... you can do that by solving this equation \[a_n = a_1+(n-1)d\] where a1 is the first term and a_n is the last.
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