Question

A die is rolled 12 times. Find the chance that the face with six spots appears once among the first 6 rolls, and once among the next 6 rolls.

Answer 1

http://openstudy.com/study#/updates/51739d07e4b0050fabb92aab

Answer 2

we should caluculate( 5/6)^10

Answer 3

P( 6 spots is rolled exactly once on the first 6 throws & 6 spots is rolled exactly once on next 6 throws)

Answer 4

probability of rolling a 6 is 1/6
let X = number of 6's rolled on first 6 rolls
X is a binomial random variable
n=6, p = 1/6 ,
P( X = 1 ) = 6C1 * (1/6)^1*(5/6)^5
Let Y = number of 6's rolled on next 6 rolls
Y is a binomial random variable
n=6, p = 1/6 ,
P( Y = 1 ) = 6C1 * (1/6)^1*(5/6)^5

Answer 5

P(X = 6 & Y=6) = P(X=6)*P(Y=6) (since they are independent)
= 6C1 * (1/6)^1*(5/6)^5*6C1 * (1/6)^1*(5/6)^5
= (5/6)^10

Answer 6

@dinakar Yes, you should calculate (5/6)^10

Answer 7

sry to ask u symbol(^) means multiplication

Answer 8

it means x^2 = x*x
2^2 = 4

Answer 9

(5/6)^10= (5/6)*(5/6)*(5/6)*(5/6)*(5/6)*(5/6)*(5/6)*(5/6)*(5/6)*(5/6)

Answer 10

0.1615

Answer 11

yes it was crct thanks