Question

Solve by completing the square.
A.
{2, 6}
B.
{2, –6}
C.
{–2, 6}
D.
{–2, –6}


Please select the best answer from the choices provided

Answer 1

S^2-8s+12=0

Answer 2

what would complete the square on the "s" parts?

Answer 3

s^2 -8s + _____

Answer 4

12

Answer 5

no

Answer 6

the 12 is extra baggage at the moment

Answer 7

Would I have to factor the -8?

Answer 8

a complete square is of the form:

(s+n)^2 = s^2 + 2ns + n^2

if we compare coeffs

s^2 + 2ns + n^2 = s^2 - 8s + _____ , then what does "n" have to be? and thereby n^2?

Answer 9

-4?

Answer 10

correct, and (-4)^2 = 16

lets add zero to your set up; since 16-16 = 0 ...

s^2 -8s +16 - 16 +12 = 0

Answer 11

now we can "compact" the square into its (s+n)^2 format

(s-4)^2 -4 = 0

Answer 12

Then add -4 to both sides?

Answer 13

umm, lets just add +4 to each side :) but yes

Answer 14

That's what I meant lol (s-4)^2=4

Answer 15

good, now lets sqrt, and solve for s

Answer 16

The square root would be 2?

Answer 17

there are two values that when squared equal 4; (2)^2 = 4 and (-2)^2 = 4

always remember to include a +- when sqrting

Answer 18

So (x+2)=4 (x+2)=-4. then subtract 2 from both sides?

Answer 19

x=2 and x =-6?

Answer 20

let me clean that up aliitle
\[(s-4)^2=4\]
\[\sqrt{(s-4)^2}=\pm\sqrt{4}\]
\[s-4=\pm2\]
\[s-4+4=4\pm2\]
\[s=4\pm2~;~2,6\]

Answer 21

Thank you, it helped a lot. I'd rather have help on it than just get the answer.

Answer 22

youre welcome, and good luck :)