Question

Can you check and correct my answers for Algebra?!
1- 8n/8
2- 2x-2/10
3-b
4-a
5-c
6- 3x/4
7- 3p/6
8- x+11/7

Answer 1

Can you post it with another format, because I cant open it.

Answer 2

The first one is wrong, what did you do to get to this result?

Answer 3

Is that \[\frac{8n}{8}\]?

Answer 4

yes

Answer 5

would #1 be 11n/4

Answer 6

So, when summing fractions, you think like a pizza, I know this sounds childish, but that is actually all you need.
If you have a quarter of a pizza, and you add another one, you end up with two quarters:\[\frac{1}{4}+\frac{1}{4}=\frac{2}{4}\]And not:\[\frac{2}{8}\]So, when summing fractions, the bottom remais the same (and both need to have the same number on the bottom), and the upper part is summed, so on the first one you have:\[\frac{8n}{4}+\frac{3n}{4}=\frac{11n}{4}\]Did you understand that?

Answer 7

YES thank you

Answer 8

for number 2 would it be (2x - 2)/5

Answer 9

Yeah, thats it

Answer 10

What would #3be?

Answer 11

Would it be choice B?

Answer 12

This one is a little bit harder, its not choice b, after you sum, try to make it simpler, for example: 5x+10=5(x+2), but with different numbers.

Answer 13

I've tried but thats the answer I got

Answer 14

b is correct by the way, but is not the simplest form, wich is what he asks for.

Answer 15

Oh okay, And #4 is C?

Answer 16

Yeah, thats correct. Did you got to A on #3?

Answer 17

No I got b

Answer 18

I'm really stuck on #5 and #8

Answer 19

Ok, we come back later to #3, #5 is correct, but since you said you were stuck I assume you didnt understand it. So, on a all positives and negatives are switched. You can look at it this way:\[\frac{4}{3-x}=1\left(\frac{4}{3-x}\right)\]But 1 can be written like\[\frac{-1}{-1}\]Thats what they do there, to change the signs. You see why you don't change anything when you change the signs on a division?
The second one is just a different way to write the first and doesn't change anything.
Now the third one, is wrong, do you see why?

Answer 20

No I;m not sure why

Answer 21

Ok, the first and the second are the same, because you multiplied the top part AND the bottom part by the same number, wich is the same as multiplying everything by 1.
Now on the c choice, the bottom part continues the same, and only the upper part is multiplied, that makes it take the opposite value, the negative one, because you are not multiplying the bottom too.

Answer 22

Oh ok i get it now! Thanks. For #7 would it be 1p/6

Answer 23

Yep, thats the answer of #7

Answer 24

What would be the answer for 8?

Answer 25

Wait, we skipped #6

Answer 26

6 is 5x/4

Answer 27

Yep, now on the #8, you are subtracting *everything* on the right side, from everything on the left side. The operation is the same as in 7, but with more terms.

Answer 28

I get that, but i just can't get the answr

Answer 29

is it x+5/7

Answer 30

So, the part where you are having trouble with is:\[(x+8)-(x-3)\]
When you have something like this, eberything on the right side is multiplied by -1, so the same thing can be written like this:\[(x+8)+(-x+3)\]Do you see it now?

Answer 31

So I would add the two together...

Answer 32

For 9 would it be A and for 10 would it be C?

Answer 33

Yep, you got it. Just to check, your #8 was 5/7 right?

Answer 34

Yes it was! Thank you sooo much

Answer 35

Just to check again was #3 b or c?

Answer 36

#3 was a, when you take the four outside, the x-2 cancels.

Answer 37

Okay thanks I kinda got confused

Answer 38

Your welcome!