Please help, I am confused! Which of the following equations can be used to calculate pOH? a) pOH=-logKw b)pOH=pKw+pH c)pOh=pKw-pH d)pOH=-log[H+] I am confused because I always thought that the equation we used for pOH was pOH=-log[OH-] But non of my answers give me that option! .

Question

Please help, I am confused! 

Which of the following equations can be used to calculate pOH? 
a) pOH=-logKw
b)pOH=pKw+pH
c)pOh=pKw-pH
d)pOH=-log[H+]

I am confused because I always thought that the equation we used for pOH was 
pOH=-log[OH-] 
But non of my answers give me that option! >.<

frostbite · Answer

Hehe I can see the problem. It sure is :) but there is a another answer that go along with your answer. How good are you with logarithms?

anonymous · Answer

waiitt! I GET IT! 
it's pOH=pKw-pH
because pKw= pOh+pH!

anonymous · Answer

right? 0.o haha

frostbite · Answer

Exactly. :)

anonymous · Answer

pKa+pKb = pKw which is same thing as =14
pOH+pH = 14 
Goob job!

anonymous · Answer

@Frostbite Oxidation half ?

anonymous · Answer

Thank you guys! 
I didn't really think things through! 
I appreciate your help(: