1. If 9 students sharpen 18 pencils in 2 minutes, how many students will it take to sharpen 18 pencils in 1 minute? A.) 2 B.) 9 C.) 18 D.) 36 2. If y varies inversely with x, and y = –16 when x = –64, what is the constant of variation? A.) 16 B.) 64 C.) 100 D.) 1,024 3. The pair of points (3, 8) and (x, 6) are on the graph of an inverse variation. What is the missing value? A.) 4 B.) 3 C.) -1 D.) 1
1)c
3) d i think
4. The weight needed to balance a lever varies inversely with the distance from the fulcrum to the weight. A 120-lb weight is placed on a lever, 5 ft from the fulcrum. What amount of weight, in pounds, should be placed 8 ft from the fulcrum to balance the lever? A.) 120 B.) 75 C.) 8 D.) 125 5. In the inverse variation equation xy/4 = -3, what is the constant of variation? A.) -3 B.) 4 C.) -12 D.) -3/4 6. What is the graph of y = 4/x?
4) d i think
I need help not people guessing. @skinny23
5) c
sorry..
Did you just guess on all? @skinny23
no
Which ones did you guess on? @skinny23
just 3 n 4 cuz i dont know them for sure
What about number one?
number 1 is c
How?
because if it takes 2 minutes for 9 people to sharpen 18 pencils then if you double the students for one minute
For 2, if y varies inversely with x, then \(\Large y = {k \over x}\) where k is the constant of variation, when y = -16 x = -64 so \(\Large -16 = \frac{k}{-64}\), \(k = -16 * - 64 = 1024\) For 3, same kind of approach: y = k/x, when x = 3, y = 8 so k = 24 y = 24/x (x, 6) is on the graph y = 24/x so 6 = 24/x, x = 4
What about 4 or 5? @Meepi
4. The weight needed to balance a lever varies inversely with the distance from the fulcrum to the weight. A 120-lb weight is placed on a lever, 5 ft from the fulcrum. What amount of weight, in pounds, should be placed 8 ft from the fulcrum to balance the lever? (1 point) 120 75<<<<<answer 8 125
\[120 * 5 = 8 * x \] \[8 \div 600 = 8x \div 8\]\[75 = x\]
oh n 6. btw is a graph this is the right answer
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