If the cost of manufacturing x items is x^3 + 20x^2 + 90x + 15 , find the marginal cost function and compare the marginal cost at x = 50 and the actual cost of manufacturing the 50th item.
@Meepi can u help?
I did it but my teacher said I got it wrong here is what i did f’(x) = x^3 + 20x^2 + 90x + 15 = 3x^2 + 40x + 90 50^3 + 20(500^2 + 90(50) + 15 = 125015 49^3 + 20(49)^2 + 90(49) + 15 = 1082474 c(50) – c(49) = 42541 f’(x) = 3x^2 + 40 + 90 = 24590 actual cost : 42541 marginal cost: 24590
She said to Find c'(50) and recalculate c(50)-c(49).
Cost is c(x) = \(\Large x^3 + 20x^2 + 90x + 15\) Marginal cost c'(x) = \(\Large 3x^2 + 40x + 90\) Marginal cost at x = 50 is c'(50) = \[3(50)^2+40*50+90 = 3*2500 + 2090 = 9590\] Actual cost of the 50'th item: c(50) - c(49) = \(50^3 + 20(50)^2 + 90*50+15 - 49^3 - 20(49)^2 - 90*49 - 15\) = 9421
Do you have to calculate this by hand?
ok i see where i did my mistake
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