Find the equation of the line tangent to f(x)=x/((x^2)+3) at (0,0)
Just be sure, the function given is: \[f(x) = \frac{ x }{ x^2+3 }\]
And this is for Calculus?
If it is, then the first thing that you are going to do is take the derivative of the function using the quotient rule.
@jazzie -- do you know how to do that?
Yes this is for calculus ! I am preparing for a test and am kinda lost when it comes to this @MoonlitFate
Ah, okay. Well, does taking the derivative of that confuse you?
Isnt the derivative (3-x^2)/((x^2) +3)^2)
Yes. Sorry, I was working it out.
Okay, I'm used to doing simpler problems, but what I would usually do is set x to 0 in the derivative and work it out to get the y-intercept.
Okay if it helps these are my options x – 3y = 0 y – 3x = 0 x + 3y = 0 y + 3x = 0 Does not exist.
I got does not exist; but, I'll verify it, real quick.
Hmm, I did that wrong...
Okay the tangent is where the two lines touch ?
The tangent line is a line that touches a curve at a certain, but it doesn't cross over it.
they just touch. okay so i could graph it and find the point ?
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