Question

Anyone want to please help?:)

Answer 1

After \[\frac{ x+1 }{ 3 }-\frac{ x+2 }{ 2x }\] have been combined using the Least Common Denominator of 6x, what is the numerator?

Answer 2

Answer choices:
a. 2x2 - x + 2
b. -2x2 - x + 3
c. 2x2 - x - 6
d. -x2 + x + 3

Answer 3

how can you make appear 6x in the denominator?

Answer 4

Multiply it.

Answer 5

I tried working the problem out but the answer I got is different from the answer choices

Answer 6

nice ..so what is the numbers you need to multiply both of those 2?

Answer 7

with what should you multiply each of those 2 fractions?

Answer 8

This is what I did:
\[2x(x+2) - 3(x+1)\]
\[2x ^{2}+4x-3x-3\]
\[2x ^{2}+x-3\]

Answer 9

hmm lets start from the 1st (left fraction) ...what you need to multiply it with so that 6x appears in the denominator?

Answer 10

2x and 3 but wouldn't that give me -6?

Answer 11

2x(x+1)-3(x+2) right?

Answer 12

you wrote 2x(x+2) - 3(x+1) i dont know why

Answer 13

I wrote it like that because I figured that was it's place because the original equation is \[\frac{ x+1 }{ 3 }-\frac{ x+2 }{ 2x }\]

Answer 14

if you multiply the left fraction by 2x what do you take for the left fraction?

Answer 15

sorry multiply by 2x/2x

Answer 16

\[4x ^{2}\]

Answer 17

no i mean
\[\frac{ 2x }{ 2x }\]

Answer 18

oh sorry!! 1

Answer 19

no multiply \[\frac{ 2x }{ 2x }\] with\[\frac{ x+1 }{ 3 }\]what do you take?

Answer 20

\[\frac{ 2 }{ 2 }* \frac{ x+1 }{ 3 } ............. \frac{ 2x+2 }{ 6 }\]

Answer 21

\[\frac{ 2x(x+1) }{ 2x*3}\]

Answer 22

you need to have 6x in the denominator

Answer 23

Oh true true I didn't plug in the x in there

Answer 24

nice that you understood that :p now make the same with the second fraction on the right...
multiply that with \[\frac{ 3 }{ 3}\]

Answer 25

\[\frac{ 3 }{ 3 }* \frac{ x+2 }{ 2x }....\frac{ 3x+6 }{ 6x }\]

Answer 26

now what do we have for the 2 fractions?

Answer 27

\[\frac{ 3x+6 }{ 6x } ? \frac{ 2x+2 }{ 6x }\]

Answer 28

would it be minus?

Answer 29

you put the second fraction on the left side and the first on the left..why you reversed them?

Answer 30

put the fraction we found first minus the fraction we found second

Answer 31

can i ask where are u stuck?

Answer 32

\[\frac{ 2x ^{2}+2x }{ 6x }-\frac{ 3x+6 }{ 6x }= 2x ^{2}-x+6 \]

Answer 33

Or would it be -6?

Answer 34

its -(3x+6) so it would be -6

Answer 35

I see!! Damn Thanks!!!

Answer 36

you understood the procedure?:p

Answer 37

Yes, wow thanks a lot!!:)

Answer 38

nice,np at all