Question

Who ever can help me with my calculus questions, I will appreciate their help :)So can you help me?

Answer 1

what is the question?

Answer 2

r u still there @ satellite?

Answer 3

Hey, what is the question?

Answer 4

oh ok yeah the question is :

Answer 5

\[f ' (x) = 2x ^{2/3}+4x ^{5/3}-3x+\sqrt{5}\]

Answer 6

find f (x) when f ' (x) is given

Answer 7

can you please help me to understand this whole question bcoz my professor didnt help tht much

Answer 8

hi

Answer 9

you have to find the integral

Answer 10

yes

Answer 11

6/5x^(5/3)+3x^(8/3)-3/2x^(2)+sqrt(5)x+C

Answer 12

ok, so it might help to have a table of integrals, but I can walk you through it
the integral of x^n dx=(1/(n+1))*(x^(n+1))

Answer 13

alright thanks :)

Answer 14

so you use that for each of the pieces of f'(x), and you have to add a constant at the end
so it is (6/5)*x^(5/3)+(3/2)*(x^8/3)-(3/2)*x^2-sq(5)*x+C

Answer 15

right the 3 should be 3/2

Answer 16

sometimes it is helpful to look at the before and after and figure out what you have to multiply by to get from the derivative to the original function

Answer 17

ok

Answer 18

so thats my answer?

Answer 19

Anyone help !! I need to submit my homework today :(

Answer 20

Before you take the integral you have to find the anti-derivative so if f'(x) is the derivative what is f(x). Then you can plug in the integral from a to b for x and solve from there. remember its F(b)-F(a)

Answer 21

Does this help?