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Physics 12 Online
OpenStudy (anonymous):

An electron of kinetic energy 45 keV moves in a counter-clockwise circular orbit perpendicular to a magnetic field of 0.325 T. Calculate the acceleration of the electron.

OpenStudy (anonymous):

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OpenStudy (anonymous):

electron is moving in a magnetic field. so, it experience a magnetic force \[F_B=qvB\\ m_ea = qvB \] me = mass of electron a = acceleratio n-> to find q = charge of electron v = velocity of electron -> get it from the Kinetic energy B = magnetic field intensity -> given

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