4a+12
-------
a+3
Select the appropriate restrictions for the variables.
A.
a≠3
B.
a≠4
C.
a≠–3
D.
There are no restrictions on the values of variable a
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OpenStudy (skullpatrol):
Any ideas?
OpenStudy (anonymous):
just revising my work before i sent it in.
OpenStudy (skullpatrol):
Do know how the word "restriction" is used in Algebra?
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
there is none.
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OpenStudy (skullpatrol):
$$\frac{4a+12}{a+3}$$are you saying there is no restriction on this expression?
OpenStudy (anonymous):
its 3..
OpenStudy (skullpatrol):
What is 3?
OpenStudy (anonymous):
idk man i just pooped myself....
OpenStudy (anonymous):
I just need help in this mang.
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OpenStudy (anonymous):
answer or not i gotta go poop so brb and type ur answer or w.e im kinda holding my butcheecks together.
OpenStudy (skullpatrol):
Remember that you cannot divide by zero.
You must $$restrict$$ the variables in a denominator by excluding any values that make the denominator equal to $$zero.$$