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Mathematics 22 Online
OpenStudy (anonymous):

4a+12 ------- a+3 Select the appropriate restrictions for the variables. A. a≠3 B. a≠4 C. a≠–3 D. There are no restrictions on the values of variable a

OpenStudy (skullpatrol):

Any ideas?

OpenStudy (anonymous):

just revising my work before i sent it in.

OpenStudy (skullpatrol):

Do know how the word "restriction" is used in Algebra?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

there is none.

OpenStudy (skullpatrol):

$$\frac{4a+12}{a+3}$$are you saying there is no restriction on this expression?

OpenStudy (anonymous):

its 3..

OpenStudy (skullpatrol):

What is 3?

OpenStudy (anonymous):

idk man i just pooped myself....

OpenStudy (anonymous):

I just need help in this mang.

OpenStudy (anonymous):

answer or not i gotta go poop so brb and type ur answer or w.e im kinda holding my butcheecks together.

OpenStudy (skullpatrol):

Remember that you cannot divide by zero. You must $$restrict$$ the variables in a denominator by excluding any values that make the denominator equal to $$zero.$$

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