Question

Consider an x-ray tube with a Cu anode and a monochromator consisting of a nickel single crystal with (111) planes parallel to the surface of the crystal. What is the lowest voltage capable of producing x-rays through a monochromator?

Answer 1

3053

Answer 2

lol how do you even do this?

Answer 3

λ = 2diii sinθ => λmax=2diii θ=90
eV = hc/λsw => smallest voltage => longest wavelength capable of diffraction

\[diii=\frac{ a }{ \sqrt{1^{2}+1^{2}+1^{2}}} \]
α = 3.53*10^-8 cm
\[d_{iii}=2.04*10^{-8} cm\]
\[λ_{\max}=4.07*10^{-8}cm\]
\[V=\frac{ \left( 6.626*10^{-34} \right)\left( 3*10^{8} \right) }{ \left( 1.6*10^{-19} \right)\left( 4.07*10^{-10} \right) } = 3053 V\]