On your birthday, you deposit $540.00 in an account that pays 6% interest, compounded annually. How much is in the account 3 years later? (1 point) a.$637.20 b.$543.18 c.$643.15 d.$1,717.20
remember the formula for compount interest here we have principal P =540 interest rate r= 0.06 compounded anually so n=1 and time is t=3
Compound interest formula is M = P(1 + i)^n Where M = the final amount P = the principal i = interest rat per year n = number of years invested M = 540(1 + 0.06)^3
You first do what's in the parenthesis. so 1 + .06 =?
that is a decimal before the 06
okay, now you calculate 1.06 to the power of 3
powers are the number multiplied by itself, that many times so it would be the same as saying (1.06)(1.06)(1.06)
1.06 * 1.06 =?
you're adding them together and you need to be multiplying them
very good, now multiply that number by the amount being invested which is 540
and since you're dealing with money you'll need to round to the nearest 2 decimal places.
so that number rounded off should give you?
You would be correct.
anytime
sure
The simple interest formula is I = Prt Where I = the interest P = the principal r = the interest rate t = the time it takes you to pay of the loan I = (500)(0.03)(2)
Solve the problem as it sits to give you A) Add the amount borrowed with the answer for A) to give you B)
the parenthesis mean those numbers are being multiplied
you need to multiple one more number into that
that's your A)
$30 in interest will be paid
B) is the sum of the principal and the interest
Unless you have another question about these problems I'd say were done. I hope that helped
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