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What would be the resulting molarity of a solution made by dissolving 31.3 grams of Ca(OH)2 in enough water to make a 1050-milliliter solution? Show all of the work needed to solve this problem.
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\[c=\frac{ n }{ v }\] c=concentration (molarity) n=no. of moles v=volume
you can find the number of moles by \[n=\frac{ m }{ M }\]
.402 g/mol or .402 mols?
sorry it took me so long..just saw you responded
@oliver.84 n=no. of moles m=mass M=Molar mass (mass of 1 mole) which you calculated as 74.09 g/mol
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\[n=\frac{ 31.3g }{ 74.09 \frac{ g }{ mol } }\] \[n=0.422 mol\]
so what did you get for the concentration??
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