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Chemistry 10 Online
OpenStudy (anonymous):

What would be the resulting molarity of a solution made by dissolving 31.3 grams of Ca(OH)2 in enough water to make a 1050-milliliter solution? Show all of the work needed to solve this problem.

OpenStudy (anonymous):

\[c=\frac{ n }{ v }\] c=concentration (molarity) n=no. of moles v=volume

OpenStudy (anonymous):

you can find the number of moles by \[n=\frac{ m }{ M }\]

OpenStudy (anonymous):

.402 g/mol or .402 mols?

OpenStudy (anonymous):

sorry it took me so long..just saw you responded

OpenStudy (anonymous):

@oliver.84 n=no. of moles m=mass M=Molar mass (mass of 1 mole) which you calculated as 74.09 g/mol

OpenStudy (anonymous):

\[n=\frac{ 31.3g }{ 74.09 \frac{ g }{ mol } }\] \[n=0.422 mol\]

OpenStudy (anonymous):

so what did you get for the concentration??

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