Question

...

Answer 1

is it like this?
\[f(x)={x+1\over x^2-1}\qquad g(x)={3x+7\over 2x}\]

Answer 2

Yes

Answer 3

and you are asked to find \(f[g(x)]\)

Answer 4

yes

Answer 5

ok, simplifying the given functions:
\[
f(x)={\cancel{x+1}\over(x-1)\cancel{(x+1)}}\qquad g(x)={3\over 2}+{7\over x}
\]

Answer 6

it means in equation of f replace each x by g(x)
and then put value of g(x)

Answer 7

\[
f[g(x)] = \frac{1}{\left({3\over2}+{7\over2x}\right)-1}
\]

Answer 8

\[
f[g(x)]=\frac{1}{(3x+7)-2x\over 2x}\\
f[g(x)=\frac{2x}{x+7}

\]

Answer 9

THANKS! :)