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OpenStudy (goformit100):
At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party?
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OpenStudy (goformit100):
@dmezzullo @LoveYou*69
OpenStudy (amistre64):
assume there are like 3 or 4 and see if you can develop a pattern
OpenStudy (goformit100):
i did this question several time but failed to understand the logic
OpenStudy (amistre64):
3 people, each shake 2 hands; 3*2=6, but theres duplication in that
ab ba ca
ac bc cb
in reality acuality, ab bc ca is all
OpenStudy (amistre64):
4 people, 3 hands each ... 12 with duplication (or permutations they are called)
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OpenStudy (amistre64):
do we know a way to ignore order and just count groups?
OpenStudy (shamim):
ya it will b combination
OpenStudy (amistre64):
each handshake consists of 2 people, and there are n people at the party
n choose 2
OpenStudy (shamim):
ya
OpenStudy (shamim):
i know the result
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OpenStudy (amistre64):
or this simplifies to:\[\frac{n(n-1)}{2}\]
OpenStudy (shamim):
=66
OpenStudy (goformit100):
Thankyou sir
OpenStudy (amistre64):
good luck ;)
OpenStudy (shamim):
anyway i think u know the law of combination is\[c _{r}^{n}=\frac{ n !}{ r!(n-r)! }\]
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OpenStudy (shamim):
or\[66=\frac{ n! }{ 2!(n-2)! }\]
OpenStudy (shamim):
i think u got it
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