Question

2 Resistors of resistance, R = (100 +- 3) Ohm, R2 = (200+-4)Ohm are connected in Parallel and Series.

Find the absolute error and % error in the measurement of equivalent resistance are in each combinations I.e Series and Parallel.. ??

PLEASE HELP!!

Answer 1

Help!!

Answer 2

lets work series first

Answer 3

do u knw formula for equivalent resistance for resistors in series ?

Answer 4

R= R1+r2+r3...

and for parallel..

R= R.R1/R1+r2

Answer 5

good we can start from there :

when the 2 resistors are connected in series ideally we expect to see 100 + 200 = 300 ohm.
but since these are not ideal,
first resistor can change +- 3, that is, it can be anywhere between [97, 103]
second resistor can change +- 4, that is, it can be anywhere between [196, 204]

so overall, the series connection can see an absolute error of +- 7 ohm
and a % error of 7/300 * 100 = 2.33 %

Answer 6

see if the above make sense, we can do the parallel same way

Answer 7

thank you.. ^_^

Answer 8

yw ! try the parallel circuit also... ping me if u get stuck.. .

Answer 9

okay.. :D thanks alot.. ^_^

Answer 10

can you just do it for parallel too? ^_^ please

Answer 11

when the 2 resistors are connected in parallel ideally we expect to see 100 * 200/300 = 66.67 ohm.
but since these are not ideal,
first resistor can change +- 3, that is, it can be anywhere between [97, 103]
second resistor can change +- 4, that is, it can be anywhere between [196, 204]

so overall, the parallel connection can see a resistance of : [97||196 103||204]
= [64.887, 68.443]
= -1.78, +1.78
= +-1.78

so thats an absolute error of +-1.78
and a % error of 1.78/66.67*100 = 2.67 %

Answer 12

Thank you, thank you, THANK A LOT!! ^_^ :D

Answer 13

np hope u understood the working :)

Answer 14

100 * 200/300 = 66.67 ohm.

how it just come?

Answer 15

okayy.. GOT IT.. :D

Answer 16

good to hear :)