National Fuelsaver Corporation manufactures the Platinum Gasaver, a device they claim "may increase gas mileage by 22%." Here are the percent changes in gas mileage for 15 identical vehicles, as presented in one of the company's advertisements: 48.3 46.9 46.8 44.6 40.2 38.5 34.6 33.7 28.7 28.7 24.8 10.8 10.4 6.9 -12.4 Would you recommend use of a t confidence interval to estimate the mean fuel savings in the population of all such vehicles? Explain your answer.
@amistre64
there is usually a table defining a path to take that ends up in z, t, or bootstrapping
how do i find that?
um, its in all the textbooks
..
im looking in my textbook :) i believe if memory serves that if n<30 we go t
Ok!
the one i was thinking of had to do with: if sigma unknown, and data is normally distributed, use t statistic in place of z stats
ok
Would you recommend use of a t confidence interval to estimate the mean fuel savings in the population of all such vehicles? Explain your answer.
my idea at the moment, maybe we should determine if the data presented is normally distributed or not
Ok, how would i do that
a stem and leaf is a simple way to see if it is; the outline of the leafs will mimic a histogram
can u show?
you were already shown this process way back in other chapters .....
cut off the first digit and stack the rest in rows or columns
i never learned
48.3 46.9 46.8 44.6 40.2 38.5 34.6 33.7 28.7 28.7 24.8 10.8 10.4 6.9 -12.4 these are the numbers so
spose we have a set of number 23 25 27 23 29 21, the stem is the 20 parts, and the leafs are the ones 2 | 1 3 3 5 7 9
Oh ya i know how to do that
what do i do with the negative value tho ? the -12.4
place it on the other side of a 0 :)
-1| 0| 1| 2| 3| 4| 5|
-1| 2 0| 1| 2| 4.8 3| 4| 5|
you can make columns instead .. but thats difficult to format up on here
on the right track?^
thats on the right track yes :) but -1|2.4
for simplicity, the numbers dont really have to be in order ... just stacked in the right row is all
oh ok
its the shape that we are after
..and if anyone else looking in here has a better solution to this post, feel free to chime in :)
-1| 2.4 0| 1| 0.4 0.8 2| 4.8 8.7 3| 3.7 4.6 8.5 4| 0.2 6.4 6.8 6.9 8.3 5| 6| .9
is that right.. it hard to do here
that 6.9 should be seen as 06.9 since we are cutting off the ten spots
ok how should the end table look ?
-1| 2.4 0| 6.9 1| 0.4 0.8 2| 4.8 8.7 8.7 3| 3.7 4.6 8.5 4| 0.2 6.8 6.9 8.3 4.6 thats seems about right
ok cool thx
from the looks of this data, its skewed, and not normally distributed
So that ould be my answer?^
--> The data appears to be skewed, and NOT normally distributed.
correct, and im trying to recall if the t statistic is related to the population, or the sample distribution at the moment
thx!
i have one more prob im posting now, can u look ?:P
i found the chart in my book :) is sigma known? No. Is the pop normally distibuted? If yes, t stat If no, check n size dunno? id conservatively go with no is n>30? no use nonparametric of boot strapping methods then
that would personally be my "reasoning"
Join our real-time social learning platform and learn together with your friends!