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OpenStudy (anonymous):
Which of the following is a foci of the conic section with the equation x^2/16-y^2/4=1
(2squareroot5,0)
(0,2squareroot5)
(2squareroot3,0)
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OpenStudy (mertsj):
I see this is exactly like the previous problem you posted. Would you like to learn to solve these problems yourself?
OpenStudy (anonymous):
yes !
OpenStudy (mertsj):
The foci are c units from the center do you know that?
OpenStudy (anonymous):
no..?
OpenStudy (mertsj):
Well, you know that now. It is always the case. Then you have to know whether the hyperbola opens up and down or right and left. Which does this do?
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OpenStudy (mertsj):
Ok. let's approach it a slightly different way:
\[\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\]
OpenStudy (mertsj):
This is the equation of a hyperbola that opens to the right and left because the x^2 term is positive.
OpenStudy (mertsj):
The center is (h,k)
OpenStudy (mertsj):
a^2+b^2=c^2
OpenStudy (mertsj):
Now can you find your foci?
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OpenStudy (anonymous):
okay i know that !
OpenStudy (mertsj):
So you can find c?
OpenStudy (mertsj):
And the center?
OpenStudy (anonymous):
so it would be A !
OpenStudy (anonymous):
right or wrong ?
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OpenStudy (mertsj):
Very good!!
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