how do i solve a problem like this 2x-25

Question

anonymous · Answer

2x-25 = (x+5)(x-5) x=-5, +5

anonymous · Answer

Thank you!!!! this helped out a lot

anonymous · Answer

anytime :)

anonymous · Answer

@redred413 can you explain how she did this please!

anonymous · Answer

nada bit sorry :( im not good at math

anonymous · Answer

ahh alright lol

anonymous · Answer

@.Sam. hey can you show me how she did this problem?

anonymous · Answer

@phi hey can you show me how she did this problem?

anonymous · Answer

@nubeer 
@chmvijay hey can you one of you show me how she solved the problem?

nubeer · Answer

$$2x-25 $$
is this your question?

anonymous · Answer

yes!

nubeer · Answer

or 
$$x ^{2}-25$$

anonymous · Answer

no the first one was right 2x-25

nubeer · Answer

2x -25 =0
1) add 25 on both sides.
2) divide both sides by 2

chmvijay · Answer

LOL she mentioned two factors for X not one if you do by ur method only +5 will get what about -5

phi · Answer

***how do i solve a problem like this 2x-25****

this is not solvable unless it is an equation

if you had    2x-25=0  you can find the x that makes it true.
see post by nubeer for details

phi · Answer

if the expression was
$$ x^2 -25 $$
you could not "solve it", but you could factor it... write it in a different way that means the same thing.   This would be a "difference of squares"  and you would use the rule
$$ (a^2 - b^2)= (a-b)(a+b) $$

for this problem you would do this
$$ x^2 -25 = (x-5)(x+5) $$

anonymous · Answer

ohh so it is pretty much i just need find the GCF

anonymous · Answer

and use the equation