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Chemistry 19 Online
OpenStudy (anonymous):

(Solutions & Precipitate help, not sure how to do these) 10) A saturated solution of KClO3 is formed from one hundred grams of water. If the saturated solution is cooled from 90°C to 50°C, how many grams of precipitate are formed? 11) A saturated solution of NH4Cl is formed from one hundred grams of water. If the saturated solution is cooled from 80°C to 40°C, how many grams of precipitate are formed?

OpenStudy (anonymous):

OpenStudy (anonymous):

from the graph, Q10) at 90degrees, amount of KClO3 solute = 50g (approx) at 50degrees, amount of KClO3 solute = 20g (approx) amount precipitated = 50-20 = 30g

OpenStudy (anonymous):

Q11) at 80degrees, amount of NH4Cl solute = 65g (approx) at 40degrees, amount of NH4Cl solute = 45g (approx) amount precipitated = 65-45 = 20g

OpenStudy (anonymous):

hard

OpenStudy (anonymous):

Thanks so much! @electrokid I appreciate it!

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