Determine whether the problem should be solved using the formula for an arithmetic sequence, arithmetic series, geometric sequence, or geometric series. Explain your answer in complete sentences. You do not need to solve. Jackie deposited $5 into a checking account in February. For each month following, the deposit amount was doubled. How much money was deposited in the checking account in the month of August?
@snowman97 Can you help me out ?:)
sure
Do you know the answer to my problem?
have answer choices
Determine whether the problem should be solved using the formula for an arithmetic sequence, arithmetic series, geometric sequence, or geometric series. Explain your answer in complete sentences. You do not need to solve.
you have to use gp with r=5, and then sum i hope this helps
@yashdhanuka Thank you so much, can you help me with a few more of these exact problems.. they confuse me
A local grocery store stacks the soup cans in such a way that each row has 2 fewer cans than the row below it. If there are 32 cans on the bottom row, how many total cans are on the bottom 14 rows?
yes sure:D will be glad to help you.
shouldn't the geometric series have common ratio as 2???
Wait what does gp stand for haha
omg! am sorry yes i typed 5 by mistaske xavier is absolutely right.
haha but what does gp stand for?
geometric progression :D
so it is geometric series?
yes
yes
okay so A local grocery store stacks the soup cans in such a way that each row has 2 fewer cans than the row below it. If there are 32 cans on the bottom row, how many total cans are on the bottom 14 rows? this is geometric series?
This is a question of Arithmetic Progression and not that of a GP. Let number of cans in the top most row be = a In this case the common difference (d) = 2 According to the question there are 14 rows in all. And the Bottom Row ( 14th ) has 32 cans. Hence ----- => 32 = [ a + ( 14 - 1 ) 2 ] => a = 6 We have now to calculate total number (N) of cans in the whole lot. => N = ( 14/2 ) [ 6 + 32 ] = 266 .
nope... here your number of cans in each row always differ by 2... i.e. d,d-2,n-4,n-6 and so on... this is an arithmetic series
@nomad96 did you understand?
Alright now what would Jackie deposited $5 into a checking account in February. For each month following, the deposit amount was doubled. How much money was deposited in the checking account in the month of August? be
nomad until and unless you do the sums on your own you will never understand :D
but it says you dont have to solve them
I already know how to solve sequences and series, I did 4 lessons on it
:) thats really nice :D
So can you just help me? I really am stuck on this
sure a[r^n-1]/[r-1] so by substituion as there are 6 months n=6 so we get 5 * 63 :D
and what sequence or series would that be?
its an gp and we use the formula for sum of gp :D
geometric sequence?
yes :)
yay thanks :) what about A major US city reports a 12% increase in decoration sales during the yearly holiday season. If decoration sales were 8 million in 1998, how much did the city report in total decoration sales by the end of 2004?
Total no of years to be considered = ( 2004 - 1998 ) = 6 years. According to the problem, Total sale in the year 1998 was = 8 M , Hence -- Total sale in 2004 => 8 [ 1 + (12/100) ]⁶ = 15.79058148 M
So it would be geometric series
yes :D
A fireplace contains 46 bricks along its bottom row. If each row above decreases by 4 bricks, how many bricks are on the 12th row? This would be arithmetic sequence?
yes :) whats your name?
nomad
sweet name <3
I was just kidding but thanks
Using complete sentences, explain the difference between an exponential function and a geometric series.
last one !!:)
Let r = e^(1/n) Integral_[0,1] e*x dx = lim_(n --> oo) [1 + r + r^2 + ... + r^(n-1)]/n = ( r^n - 1)/ n ( r - 1) = (e - 1)/ denominator denominator D(n) = (e^(1/n) - 1)/(1/n) --> d/dx (e^(x)) at x = 0 = 1 Therefore Integral _[0.1] e^x dx = e - 1 ---- Interest : rate r %compounded every 3 months. Money in account after 1 year: M)1) = (1 + r/400)^4 M(0) Compound n times per year :M(1) = ( 1 + (1/n)(r/100))^n M(0)) Continuous compounding: n --> oo M(1) = e^(r/00) M(0) Best I can do.
why dont you reply? :(
Sorry I stepped outside for a min @yashdhanuka
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