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Find the exact area of the surface obtained by rotating the curve about the x-axis. y=sqrt(4x) 0
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|dw:1367026833039:dw|\[y=\sqrt{4x}~\Rightarrow ~ \frac{dy}{dx}=\frac{2}{\sqrt{4x}}\] The area will be given by the integral \[A=2\pi\int_0^4\sqrt{4x}\sqrt{1+\left(\frac{2}{\sqrt{4x}}\right)^2}~dx\]
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