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Mathematics 7 Online
OpenStudy (anonymous):

Find the rangeeeeeeeeee

OpenStudy (e.mccormick):

\(\sin(\sin x)+\cos (\sin x)\) Who thinks these up? Hehe OK, you know that the range of just \(\sin x\) is [0,1]. However, that will be the domain of the outer functions.

terenzreignz (terenzreignz):

\[\Large * [-1 , 1]\]

OpenStudy (e.mccormick):

Oops! yak, -1,1. I am at work and having to answer othe quesions too. LOL

OpenStudy (anonymous):

its impossible to find the range of this function

OpenStudy (e.mccormick):

Don't trust wolframalpha. It does not know what \(\sqrt[3]{-1}\) means.

OpenStudy (anonymous):

i don't know how to proceed further

OpenStudy (e.mccormick):

It is graphable, so you have something to aim for just by looking at the graph: https://www.desmos.com/calculator/fgtlvxqx5t Now to see how to gt that mathematically.

OpenStudy (anonymous):

srry , but i didn't understand

OpenStudy (e.mccormick):

Is this considered trig, or calculus?

OpenStudy (e.mccormick):

If it is calculus, use derivative tests to find the min/max values. For trig, it is a litle tricker.

OpenStudy (anonymous):

okay

OpenStudy (e.mccormick):

Okay? So which is it? What class are yu taking? Are you expected to use calculus to solve this?

OpenStudy (anonymous):

+2

OpenStudy (e.mccormick):

According to that graph, the range is approximately \((-.301,1.414)\), but I bet your teacher will want exact values. How they are found depends on what you are learning or have learned.

OpenStudy (anonymous):

u r right

OpenStudy (anonymous):

how can we draw a graph of sinx+cosx

OpenStudy (e.mccormick):

If you min/max it, you will have the local and absolute minimum and maximum points. Plot those. Then use the slope of the tangent line coming in and out to approximate where to draw based on if it is going up or down.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

i have a question , which i posted thrice a day i just want to confirm that the statement is true or false

OpenStudy (anonymous):

should i post it

OpenStudy (e.mccormick):

Yes, I saw that before. I was not sure what the question meant, so I did not try to answer it. You see, I am not used to saying 128 is a member of... and 496 is not a member of... I can tell you that 128 is a power of 2. \(2^7=128\) But for factors... hmmm...

OpenStudy (anonymous):

okay no pblm thank u

OpenStudy (e.mccormick):

However,t hat does mean you can factor 128 into a chain fo positive numbers. \(2^8=256\) and \(2^9=512\) so it does skip 496.

OpenStudy (anonymous):

can u solve it step by step plsee

OpenStudy (e.mccormick):

128∈ {x : the sum all the positive factors of x is 2y } means: 128 is an element in x, such that the sum all the positive factors of x is 2y. Is there supposed toeba an of in there? sum of? Probably. \(128= 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\) So those are the positive factors of 128. Therefore the sum of the positive factors is \(2+2+2+2+2+2+2=14\) If \(y=7\), then \(2y=14\). So it might be true, depends on what y is defined as. That is why I did not know how to answer that one. I am not sure where they are getting the y from.

OpenStudy (anonymous):

okay

OpenStudy (e.mccormick):

496∉ {y : the sum of all the positive factors of y is 2y } means: 496 is not an element in y, such that the sum of all the positive factors of y is 2y. This might be solveable. \(496 = 2\cdot 2\cdot 2\cdot 2\cdot 31 \therefore \) the positive factors. \(2+ 2+2+2+31=39\) and \(2y=2(496)\implies 2y=992\) and \(\because 992\ne 93\) the statement that 496 is NOT an element in this is true.

OpenStudy (anonymous):

93?

OpenStudy (e.mccormick):

Mistyped. Meant 39.

OpenStudy (e.mccormick):

\(993\ne 39\)

OpenStudy (anonymous):

thank u

OpenStudy (e.mccormick):

So I am not sure on the first, but if you understand the math and symbols, I hope you can see why I say the second is true.

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