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A pizza place offers 6 different cheeses and 12 different toppings. In how many ways can a pizza be made with 1 cheese and 3 toppings?
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If the order of the toppings does not matter the number of combinations of toppings is \[12C3=\frac{12!}{3!9!}=\frac{12\times 11\times 10}{3\times 2}\] Each combination of toppings can be had with a choice of 6 different cheese. The number of different ways of making a pizza is \[\frac{6\times 12\times 11\times 10}{3\times 2}\]
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