Question

Simplify trig identity

Answer 1

@jim_thompson5910 the answer i got was Sin(A)+Cos(A) but apparently it is wrong :(

Answer 2

@e.mccormick

Answer 3

Well, let me look...

Answer 4

First, did you do this?
\[\frac{1+\cot A}{\csc A}\implies \frac{1+\frac{\sin A}{\cos A}}{\frac{1}{\sin A}}\]

Answer 5

yes except for cotA i put \[\cos A/\]

Answer 6

sorry CosA/Sin A

Answer 7

tan is \[\sin A/\cos A\]

Answer 8

Oh, yah... LOL It would be that.

Answer 9

\[\frac{1+\frac{\cos A}{\sin A}}{\frac{1}{\sin A}}\implies
\left[1+\frac{\cos A}{\sin A} \right]\cdot \frac{\sin A}{1}\]

Answer 10

OK... Then.... ummmm.... how the heck is that wrong!

Answer 11

Yeah! i have no idea. i actually put it in twice just to make sure but nope it wrong

Answer 12

Did you try reversing them? Who knows. ANd putting in the () just like they have it?

Answer 13

nope..it didnt work

Answer 14

maybe it's case sensitive

try cos(A) instead of Cos(A)

Answer 15

but yeah I'm getting cos(A) + sin(A) or sin(A) + cos(A) too

Answer 16

i didnt have to type it..the button for cos is there already so i just click that

Answer 17

ok show us how you're inputting the answer, maybe that will help

Answer 18

those are all the answers

Answer 19

well the only option not covered is cos(a) + sin(a)

but that's basically the same as the other options

Answer 20

yeah and I only have one more answer left so i dont want to risk it loll

Answer 21

I would bring this up with a teacher and the teacher will be able to fix the error

Answer 22

maybe i will just ask my professor thanks to everyone that helped me out!!

Answer 23

does anyone know how to do this \[\cot (x)/\csc(-x)\]

Answer 24

@e.mccormick

Answer 25

Simplify, solve, what?

Answer 26

cot(x) = cos(x)/sin(x)

-------------------------

csc(-x) = 1/sin(-x)

csc(-x) = 1/(-sin(x))

csc(-x) = -1/sin(x)

Answer 27

use those facts to simplify

Answer 28

simplify

Answer 29

Yah, even odd properties.