Question

2x3 - 5x2y + xy2 + 2y3

a. Simplify (2x2 + y2)(x - 2y) = ?
b. Simplify (2x + y)(x2 -3xy + 2y 2 ) = ?

Answer 1

where is c and d?

Answer 2

\[2\,{x}^{3}-5\,{x}^{2}y+x{y}^{2}+2\,{y}^{3}\]

did you mean that?

Answer 3

yes

Answer 4

ooh where are c and d then :) i got my own answer can i see c and d?

Answer 5

theyre not right for this

Answer 6

so far i think it is b but i feel it can be simplified further :)

Answer 7

elimination

Answer 8

its a

Answer 9

;)

Answer 10

was it a?

Answer 11

well i get :)

(-y+x)*(x-2*y)*(y+2*x) fully factored

Answer 12

idk

Answer 13

:) i'll check a and b :)

Answer 14

i dont think it is a :(

Answer 15

now for b

Answer 16

its b!!!!!!!!!!!!!!!!!!:)))))))))))))))))))))))))))

Answer 17

told ya ;)

Answer 18

and i check to and it is b :D

Answer 19

If you know algrabeic long division then there is a theory of if you divide your given polynomial in this case

2x3 - 5x2y + xy2 + 2y3

by a suspected binomial or trinomial

(2x + y) or (x2 -3xy + 2y 2 )

^ those are from B the 2 expressions inside the ( )

and you get 0 then that trinomial or binomial is a factor and therfore part of the answer :)

Answer 20

if you get a remainder of 0 :P

Answer 21

in other words
2x3 - 5x2y + xy2 + 2y3
-------------------- = (x2 -3xy + 2y 2 ) with no remainder
(2x + y)

and obviously

2x3 - 5x2y + xy2 + 2y3
--------------------- = 2x+y with no remainder
(x2 -3xy + 2y 2 )

Answer 22

But if you dont know algabreic long division dont bother with that method :P