Solve cos(x)(cosx+1)=0 @terenzreignz :)
answer choices A,B,C,D from top to bottom :) **I'm not too sure, but I'm leaning towards A... what do you think? :)
Same technique..., even though it's not really necessary, replace cos(x) with u u(u+1) = 0 Possible values for u?
0, -1 ?
Yup.... so cos(x) =0 cos(x) =-1 Possible values for x?
pi, pi/2, 3pi/2, and 2pi ?
or 90, 180, 270, 360 degrees?
2pi? \[\Large \cos(2\pi) = 1\]
yup! 1=1 :)
We don't have a \(\large \cos(x) = 1\)
im not following :( what do u mean?
\(2\pi\) is not a solution... Because we only have cos(x) = 0 and cos(x) = -1 We do NOT HAVE cos(s) = 1
okay... so whats next then? :/
cos(x) *
What's next? You have not even finalised your answer for the current step... What are the values for x which would make cos(x) = 0 or cos(x) = -1 true?
lol yeah haha i didn't mean like the next step haha i meant like how can i figure this part out.. :P lol sorry bout that! :P so do i plug pi, pi/2, 3pi/2 into cos(x) and see if they equal 0 or -1? and not 2pi tho right?
yeah, so, are the answers \(\Large \pi \ , \ \frac{\pi}{2} \ , \frac{3\pi}{2}\) correct?
i believe so... they are, aren't they? :)
I'm asking you. I'm asking you to be sure.
cos(pi)= -1 cos(pi/2) = 0 cos(3pi/2) = 0 so yeah right? sorry i probs should have included this part in the thing above lol :P
Okay. Good enough. So your final answer?
B ?
Yeah. Current Streak : 0 Best Streak : 3 You were leaning towards A... so... nope :P
hahah yeah :( back to 0 :( lol but yay! :) this one makes sense now tho!!! :) thanks!! :)
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