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Mathematics 13 Online
OpenStudy (anonymous):

solve 52x+2e^(3x)=4

OpenStudy (hunus):

What problems are you having with it?

OpenStudy (anonymous):

use numerical methods technique to solve these equations

OpenStudy (anonymous):

find x please

OpenStudy (hunus):

You give it a shot and I'll help you if you need it

OpenStudy (goformit100):

First of all for solving this question do you know the conception of : Theory of Equations And after doing that, I personally guarantee that you can on your own solve this particular question. I personally believe, the happiness of solving Mathematics on our is much better.

OpenStudy (anonymous):

help me please

ganeshie8 (ganeshie8):

this q looks hard

OpenStudy (anonymous):

Mr goformit100, thanks alottttttttttttttttttttt!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

sam (.sam.):

Yeah you have to use something like Newton's method for this

sam (.sam.):

\[ 52x+2e^{3x}=4 \\ \\ 52x=4-2e^{3x} \\ \\ x=\frac{2-e^{3x}}{26}\]

sam (.sam.):

\[\huge x_{n+1}=\frac{2-e^{3x_n}}{26}\]

sam (.sam.):

Then just keep iterating...

OpenStudy (anonymous):

thanks sam, but are you sure there is a uniqe method?

OpenStudy (anonymous):

this method is very long and looks boring! i think there is a another way

sam (.sam.):

There are other methods but I used this to solve it

sam (.sam.):

When you substitute x=1, or \(x_1\), you get \[x_1=-0.695597\] Then take \(x_1\) answer and substitute back into equation to find \(x_2\), you get \[x_2=\frac{2-e^{3(-0.695597)}}{26}=0.072150597\] Then do that until you get a constant answer \[x_3=0.029166 \\ \\ x_4=0.034944 \\ \\ x_5=0.03421 \\ \\ x_6=0.0343044 \\ \\ x_7= 0.0342925\] Then the final you'll get for "x" is approximated to \[x \approx 0.034 \]

terenzreignz (terenzreignz):

Maybe it has something to do with what you were taught recently, @sima.r ?

OpenStudy (anonymous):

thanks, your final answer is correct

OpenStudy (anonymous):

terenzreignz, its not my question, its my friend's question!

terenzreignz (terenzreignz):

Understood :)

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