Question

Simplify this expression.

Answer 1

\[\frac{ \sqrt{-1} }{ (2-4i)-(5+3i) }\]

Answer 2

Choices:
\[\frac{ -7-3i }{ 58 }\]
\[\frac{ 7+3i }{ 40 }\]
\[\frac{ -7+3i }{ 58 }\]
\[\frac{ 7-3i }{ 40 }\]

Answer 3

first of all \(\sqrt {-1}=i\)
also, you can combine like terms in denominator,
2-4i -5-3i =.... ?

Answer 4

-3 - 7i ?

Answer 5

first choice : -7-3i/58

Answer 6

First of all for solving this question do you know the conception of : Complex Numbers

And after doing that, I personally guarantee that you can on your own solve this particular question.
I personally believe, the happiness of solving Mathematics is much better.

Answer 7

-3-7i is correct :)
now, you need to multiply and divide by the conjugate of this,
which is -3+7i

Answer 8

wouldnt it be 3 + 7i for the conjugate?

Answer 9

only the sign of imaginary part changes.
so, -3 will remain -3

Answer 10

i used the 3+7i and ended up with \[\frac{ -7+3i }{ 40-42i }\]

Answer 11

if you had used -3+7i
you would have got a constant in the denominator, which simplifies things.

Answer 12

okay is see. i used the -3+7i and i got my answer as \[\frac{ -7-3i }{ 58 }\]

Answer 13

is that right?

Answer 14

let me double check...

Answer 15

\[\sqrt{-1}=i
\[\frac{ i }{2-4i-5+3i }=\frac{ i }{ -3-7i? }\]
\[\frac{ i }{-3-7i }\times \frac{ -3+7i}{ -3+7i }=\frac{ -3i-7 }{ 9+49 }=\frac{ -3i-7 }{58 }\]

Answer 16

yes, thats correct :)

Answer 17

THANKS!

Answer 18

THANKS!

Answer 19

welcome ^_^
welcome ^_^