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Mathematics 8 Online
OpenStudy (ketz):

Simplify using De Morgan's LAW: f = (qr'+q'r)'

OpenStudy (chmvijay):

who is de morgan do u know

terenzreignz (terenzreignz):

That + there is a logical AND ?

ganeshie8 (ganeshie8):

thats an inversion of xor so u should get xnor after simplifying

ganeshie8 (ganeshie8):

(qr'+q'r)' (qr')'(q'r)' (q'+r)(q+r') foil it now and simplify

OpenStudy (ketz):

What is the final simplification answer??

ganeshie8 (ganeshie8):

(q'+r)(q+r') q'q + rq + q'r' + rr' qr + q'r'

ganeshie8 (ganeshie8):

thats the final simplification using demorgan's laws. the thing to notice here is that you're taking negation of ex-or

OpenStudy (ketz):

Can the equation be further simplified?

ganeshie8 (ganeshie8):

impossible

OpenStudy (ketz):

ok thx

ganeshie8 (ganeshie8):

yw ! xor and xnor are very important gates so its good idea to remember their boolean function and truth table atleast.

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