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Mathematics 17 Online
OpenStudy (anonymous):

PROVING IDENTITIES !!!

OpenStudy (anonymous):

\[\frac{ 1-\sin x }{ \cos x } = \frac{ \cos x }{ 1 + \sin x}\]

OpenStudy (anonymous):

Cross multiply them out first and see if you get a more suitable form to work with.

OpenStudy (anonymous):

i am supposed to prove that the expression on the left hand side is equal to the expression in the right hand side....

OpenStudy (anonymous):

Not sure if I completely agree with this, I would assume that you're supposed to _verify_ that the left hand side is equal to the right hand side. Because a full proof of the above identity would require to start at any point on the left hand side. However, you want to show that the LHS=RHS, so in that case, as I mentioned before, cross multiply the both sides out: \[\Large (1-\sin x)(1+\sin x)=\cos^2x \]

OpenStudy (sumeer):

my approach is same but it may work. multiply left handside (1+sinx)cosx/(1+sinx)Icosx. than u get right hand side

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