Question

An equation of the circle whose center is (-3,1) and whose radius is 8 is
1)(x-3)2+(y+1)2=64
2)(x-3)2+(y+1)2=8
3)(x+3)2+(y-1)2=64
2)(x+3)2+(y-1)2=8

Answer 1

)(x-3)2+(y+2)2=4

Answer 2

thank you

Answer 3

It should be 2)(x-3)2+(y+2)2=4

Answer 4

If the center is \((a,b)\), It's \((x-a)^2 + (y-b)^2= \text{radius}^2=8^2\).
So the answer is \((x+3)^2+(y-1)^2=64\).

Answer 5

thank you