Question

PROVING IDENTITIES!!

Answer 1

\[\frac{ \cot x -1 }{ \cot x + 1 } = \frac{ 1- \tan x }{ 1 + \tan x }\]

Answer 2

well u can start by changing cotx into sinx and cosx..

Answer 3

\[\frac{ \frac{ \cos x }{ \sin x }-1 }{ \frac{ \cos x }{ \sin x }+1 }\]

Answer 4

yes u can go on by taking L.C.M

Answer 5

\[\frac{ \frac{ \cos x - \sin x }{ \sin x } }{ \frac{ \cos x + \sin x }{ \sin x } }\]

Answer 6

ok seems like we won't get an answer this way.. try again .. change cot x into 1/tanx
then take L.C.M

Answer 7

\[\frac{ \frac{ 1 }{ \tan x }-1 }{ \frac{ 1 }{ \tan x } + 1}\]

Answer 8

or you could have directly written cot x = 1/ tan x

Answer 9

\[\frac{ \frac{ 1- \tan x }{ \tan x } }{ \frac{ 1 + \tan x }{ \tan x } }\]

Answer 10

now those tanx in denominators would cancel out..

Answer 11

okay....i see that......thank you!