you can take any number that's not 0 and square it
it will always be positive
jimthompson5910 (jim_thompson5910):
so what this means is that r^2 = -36 has no real solutions
but it does have solutions...they're just not considered real numbers
OpenStudy (anonymous):
oh so it would be -6?
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jimthompson5910 (jim_thompson5910):
the convention is to make the letter i be equal to sqrt(-1)
so
i = sqrt(-1)
notice how if you square both sides, you'll get
i^2 = -1
jimthompson5910 (jim_thompson5910):
i = sqrt(-1) is known as an imaginary number
OpenStudy (anonymous):
okay :)
jimthompson5910 (jim_thompson5910):
technically all numbers are imaginary since we made them all up, so it's not really fair to call i = sqrt(-1) an imanigary number...but that's just how history played out
jimthompson5910 (jim_thompson5910):
imaginary*
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OpenStudy (anonymous):
oh lol so i got 6 for r cause 6x 6 is 36
jimthompson5910 (jim_thompson5910):
anyways,
i = sqrt(-1)
so we'll use this to solve for r
r^2 = -36
r = sqrt(-36)
r = ??? ... how will we use the first equation above to simplify?
jimthompson5910 (jim_thompson5910):
6 is close...but not the full story
OpenStudy (anonymous):
6 x -1?
jimthompson5910 (jim_thompson5910):
I'll give you a further hint (if you're still stuck)
r = sqrt(-36)
r = sqrt(-1)*sqrt(36)
r = ???
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jimthompson5910 (jim_thompson5910):
and remember that i = sqrt(-1)
OpenStudy (anonymous):
-6
jimthompson5910 (jim_thompson5910):
sqrt(36) = ???
OpenStudy (anonymous):
so 36 x 36?
jimthompson5910 (jim_thompson5910):
i want you to start with
r = sqrt(-1)*sqrt(36)
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jimthompson5910 (jim_thompson5910):
and replace sqrt(-1) with ???
and also replace sqrt(36) with ???
OpenStudy (anonymous):
2
jimthompson5910 (jim_thompson5910):
what did we make sqrt(-1) equal to
OpenStudy (anonymous):
i?
jimthompson5910 (jim_thompson5910):
yep
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jimthompson5910 (jim_thompson5910):
what is sqrt(36) equal to
OpenStudy (anonymous):
6?
jimthompson5910 (jim_thompson5910):
so
r = sqrt(-1)*sqrt(36)
turns into
r = i*6
which flips to
r = 6i
OpenStudy (anonymous):
why i?
jimthompson5910 (jim_thompson5910):
because i = sqrt(-1)
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jimthompson5910 (jim_thompson5910):
notice how we just replaced sqrt(-1) with i
OpenStudy (anonymous):
but is i r?
jimthompson5910 (jim_thompson5910):
no i is its own thing
OpenStudy (anonymous):
oh.. okay thanks! here's another one
jimthompson5910 (jim_thompson5910):
wait, it turns out that -6i works as well (in much in the same way -6 works for r^2 = 36)
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jimthompson5910 (jim_thompson5910):
so the two solutions to
r^2 + 36 = 0
are
r = 6i
r = -6i