Show that if P ( x ) is a linear polynomial, then the composition P o P(x) is also linear and has positive slope.
If P(x) is a linear polynomial, then it can be written \[\large P(x) = mx + b\]
How would I find Find P(P(x))?
Well, to find \(\large P(P(x))\) replace all instances of x in P(x) with another instance of P(x).
So, y = m(y=mx+b) + b?
y=m(mx+b)+b should suffice. Now simplify it. :)
y=my+m^2x+mb+b?
Why is there a y? \[\large P(x) = mx+b\\ \large P(P(x))=m(P(x))+b\\ \large P(P(x))=m(\color{blue}{mx+b})+b\] Please try simplifying it again.
P=(m^2)x+bm+b
Very good. \[\large P\circ P(x) = P(P(x))=\color{red}{m^2}x +bm+x\] And the slope is the coefficient of x (highlighted in red) Now, what can you say about this new slope?
Sorry a slight correction \[\large P\circ P(x) = P(P(x))=\color{red}{m^2}x +bm+\color{green}b\]
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