Question

Can someone make sure I am doing this right?

Answer 1

1) tan^2 x + 1 = sec^2 x. You are going to graph y = tan^2 x + 1 and y = sec^2 x. Look at each graph on the same plotting range. Then put both on the same axis. They should match point for point

Answer 2

You're doing it correctly from what it looks like....the two graphs should overlap each other.

Answer 3

Is that all I am supposed to do?

Answer 4

From what you said you should do, it seems like that is all you need to do. You plotted both graphs and then put them on the same axis and window and then showed that they overlapped, hence showing that tan^2(x) + 1 = sec^2(x)

Answer 5

If it were tan^2x+1-sec^2 2 would I graph y=tan^2x+1 and y=-sec^2 2?

Answer 6

Would I keep the negative?

Answer 7

Is tan^2(x) + 1 - sec^2(x) set equal to anything?

Answer 8

No

Answer 9

Okay, so if you were to graph that, you would put y = tan^2(x) + 1 - sec^2(x) and since you know tan^2(x) + 1 = sec^2(x), you wouldn't see anything because it would be the graph of y=0.

Answer 10

Okay, thank you!

Answer 11

No problem