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Compute the sum and the limit of the sum as n approaches infinity.
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i could swear we just did this one
Yes we did I got it wrong...my teacher said it was incorrect
Was the previous answer \(\dfrac{(n+1)(8n+1)}{6n^{2}}\)?
no, @tkhunny i got two terms one is \[\frac{ 1 }{ n^3 } \frac{ n(n + 1)(2n + 1) }{ 6 }\] and the second term \[\frac{ 1 }{ n^2} \frac{ n(n + 1)}{ 2}\] i don't know what to after that.
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How did you get that far? Did you pull out the 1/n^2?
@tkhunny yes
\(n^{3}\)? How did you get one of those?
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