Question

I don't even know how to begin this...
show that the equation 2x - 1 = sin(x) has exactly one real root

Answer 1

so i put this into wolfram and i guess i'm looking for the intersection?

Answer 2

Yes, you are correct.
The left side is just a straight line while the right side is the sine function.
We want to know at what x-value these two functions intersect.

I'm not sure how you would `actually` find the x-value, the point of intersection. That would be rather tricky.

But we can do what the direction are asking, we can `show` that they have one point of intersection by graphing the two functions.

Answer 3

\[\large y_1=2x-1\]\[\large y_2=\sin x\]
Graph these two functions separately and show that they only intersect at a single point.

Answer 4

thank you