Question

Solve and show work for the 10 problems: (3, 4, 7, 8, 10, 11, 13, 14, 19, & 20) of the following link: http://www.kutasoftware.com/FreeWorksheets/Alg2Worksheets/Solving%20Rational%20Equations.pdf
It has the answers too, but I haven't looked at them yet. Just look at the questions.
A medal will be rewarded for help.

Answer 1

The problems are very complex for me to solve and I am not trying to let anyone give me the answers.

Answer 2

I'll get you started with 3.

\[\frac{ 1 }{ 6b^{2} } + \frac{ 1 }{ 6b } = \frac{ 1 }{ b^{2} }\]
Lets get rid of the 1/ b^2 in the denominator by multiplying both side by b^2, this gives us:
\[b^{2}[\frac{ 1 }{ 6b^{2} } + \frac{ 1 }{ 6b } = \frac{ 1 }{ b^{2} }]=\frac{ 1 }{ 6 }+\frac{ b }{ 6 }=1\]
Now we can subtract both sides by 1/6. Note that 1 = 1/1 or 6/6.
\[\frac{ b }{ 6 } = \frac{ 6 }{ 6 }-\frac{ 1 }{ 6 }\]
\[\frac{ b }{ 6 }=\frac{ 5 }{ 6 }\]
Lets get rid of the 6 in the denominator to solve for b. We do this by multiplying both sides by 6, giving us:
\[b=5\]

Answer 3

@carson889 Is that the right answer

Answer 4

@goformit100 Is the answer right?

Answer 5

Yes, it is.

Answer 6

Yes your answer is correct :D well done Keep it up

Answer 7

Are you good at Algebra II?

Answer 8

No

Answer 9

or at math

Answer 10

Do you have another question?

Answer 11

Asking if it's right?

Answer 12

Logically it is sound and it matches the answer on the answer sheet

Answer 13

the answer on the sheet says 1/6, but you got b = 5

Answer 14

That would be the answer for question one.

Answer 15

I did question 3, not question one.

Answer 16

sorry! Could you do 4 more 19, 20, 4, and 7

Answer 17

4.
\[\frac{ b+6 }{ 4b^{2} }+\frac{ 3 }{ 2b^{2} }=\frac{ b+4 }{ 2b^{2} }\]
Lets multiply the second and third fraction by 2/2 so that all the numbers have the same denominator.
\[\frac{ b+6 }{ 4b^{2} }+\frac{ 6 }{ 4b^{2} }=\frac{ 2b+8 }{ 4b^{2} }\]
We can now combine like terms on the left hand side:
\[\frac{ b+12 }{ 4b^{2} }=\frac{ 2b+8 }{ 4b^{2} }\]
Now multiply both sides by 4b^2
\[b+12 = 2b + 8\]
Solve for b:
\[4 = b\]