Find the coordinates of the point which divides the line segment joining the points (1, –2, 3) and (3, 4, –5) in the ratio 2 : 3 (i) internally, and (ii) externall
@terenzreignz
What do internally and externally mean?
Probably able to use vectors again... find the vector from one point to the other, then multiply it by 2/5 or 3/5 (guessing that's internally/externally), then find it's endpoint.
if internally use +sign ..externally -ve sign
If the points are A and B, find the endpoint by adding 2/5 of the vector AB, to point A
Possibly similar to the midpoint formula, which goes \[\huge \left(\frac12(x_1+x_2),\frac12(y_1+y_2)\frac12(z_1+z_2)\right)\] Except instead of \(\large \frac12\), you multiply \(\large \frac25\) instead.
^that looks like it should work too (looks kinda like the result of what i said, just from trying to do it in my head)
OH so we can also solve it using determinant or what ?
Determinants? This looks too simple to have to resort to determinants... :/
oh
On second thought, that formula above may be too good to be true...
With vectors I think it'd be \[\large (x _{1}+\frac{ 2 }{ 5 }(x _{2}-x _{1}), y _{1}+\frac{ 2 }{ 5 }(y _{2}-y _{1}), z _{1}+\frac{ 2 }{ 5 }(z _{2}-z _{1}))\] Hopefully that's right, I'm too lazy to check on paper. It doesn't look exactly like @terenzreignz formula...
Yeah... that's more like... It's just that when you take \(\frac12\) it should result into the more nice-looking midpoint formula. Yikes... I'm losing my touch :D
Yeah I assumed yours would work too... but it only works with half because 1-1/2 = 1/2
Yup :) I learned.
Me too :) i figured that might be a handy shortcut for finding points not halfway between two points.
I guess externally, like @AravindG said, would just be subtracting 2/5. It doesn't seem to specify from which point to start from, though, and there's multiple possible points depending on which point you take the 2:5 ratio from.
@terenzreignz and @goformit100 there is actually a formula for this question (it's essentially what i posted above): http://www.learnnext.com/lesson/CBSE-X-Maths-Section-Formula.htm
It only gives for 2 dimensions but you just need to add the third in the same way.
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