Can someone help me with this question:

I am supposed to do long division on:

(x^3+4x^2-3)/(x^2-7x+6)

And I can do that, but get a product + a remainder. I need to integrate that, therefore I want to get a sum, the result will look like this:

http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427epskhbpv6se

Can someone please guide me, how to get from that to this?

Question

Can someone help me with this question:

I am supposed to do long division on:

(x^3+4x^2-3)/(x^2-7x+6)

And I can do that, but get a product + a remainder. I need to integrate that, therefore I want to get a sum, the result will look like this:

http://www.wolframalpha.com/share/clip?f=d41d8cd98f00b204e9800998ecf8427epskhbpv6se

Can someone please guide me, how to get from that to this?

.sam. · Answer

So what is your result on the division?

anonymous · Answer

$$(x+11)(x^2-7x+6)+(71x-69)$$

.sam. · Answer

Did you do it like this?

.sam. · Answer

Then put it in the form
$$\Huge (Quotient)+\frac{Remainder}{Divisor}$$

anonymous · Answer

Please clarify for me, what is Divisor in this case?
Do you mean something like this:

$$(x+11)(x^2−7x+6)+\frac{(71x−69)}{x^2-7x+6}$$
Wouldn't that disbalance the eq?

.sam. · Answer

attachment

anonymous · Answer

Yes, I am aware of their names... I stand by my previous question...

.sam. · Answer

You should get
$$(x+11)+\frac{71x-69}{x^2-7x+6}$$

anonymous · Answer

Ah, I see.. now I can do partial fractions on the other one.. Well thank you very much!

.sam. · Answer

yw