can someone please explain this problem to me?
It better be 2 + 2 = 4.
there are two jars. Jar 1 has 5 white and 8 red balls. jar 2 has 10 white and 17 red balls. we flip a coin and if its Heads, we pick from jar 1, if its tails we pick from jar 2. suppose that a white ball is selected, what is the probability that the coin landed heads?
Bayes theorem !
??
Let H be the event that the coin is heads, and W the event that the ball is white. We need to find the probability that that the coin is heads, given the ball was white... \[\Large P(H | W) = \frac{ P(W | H) P(H) }{ P(W) }\] We can also probably use a tree diagram... might be easier here.
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sorry, doyou get the final answer by dividing (5/26)/(5/26 + 10/54) ???
sorry!!!!but i am just a little confused like you use the tree diagram in order to find P(H n W) so you can put that over P(w) right???
Not quite... you have P(W) correct, though (5/26+10/54) |dw:1367139394893:dw|
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