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Mathematics 22 Online
OpenStudy (anonymous):

can someone please explain this problem to me?

Parth (parthkohli):

It better be 2 + 2 = 4.

OpenStudy (anonymous):

there are two jars. Jar 1 has 5 white and 8 red balls. jar 2 has 10 white and 17 red balls. we flip a coin and if its Heads, we pick from jar 1, if its tails we pick from jar 2. suppose that a white ball is selected, what is the probability that the coin landed heads?

OpenStudy (aravindg):

Bayes theorem !

OpenStudy (anonymous):

??

OpenStudy (aravindg):

http://en.wikipedia.org/wiki/Bayes'_theorem

OpenStudy (agent0smith):

Let H be the event that the coin is heads, and W the event that the ball is white. We need to find the probability that that the coin is heads, given the ball was white... \[\Large P(H | W) = \frac{ P(W | H) P(H) }{ P(W) }\] We can also probably use a tree diagram... might be easier here.

OpenStudy (agent0smith):

|dw:1367138406906:dw|

OpenStudy (anonymous):

sorry, doyou get the final answer by dividing (5/26)/(5/26 + 10/54) ???

OpenStudy (anonymous):

sorry!!!!but i am just a little confused like you use the tree diagram in order to find P(H n W) so you can put that over P(w) right???

OpenStudy (agent0smith):

Not quite... you have P(W) correct, though (5/26+10/54) |dw:1367139394893:dw|

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