Question

Please check my answers

Answer 1

1) its 16 = 2x - 6 so my answer was 11

im not that sure though

Answer 2

@viciousnessvicky 7 is right. @syhnaYou forgot to do the ratio.

Answer 3

Thank you, how do the others look?

Answer 4

ah yah i got it sorry

Answer 5

2... That 36... is that the angle at the top of the tree and the rope?

Answer 6

Then the law of similar triangles says?

Answer 7

i think the answer should also be 26 since the triangles are congruent

Answer 8

i mean 36

Answer 9

@syhna The triangles are similar, not congruent... now the ANGLES of a similar triangle are congruent. That is probably what you meant to say. As long as you get the concept, it works.

Answer 10

yah yah

Answer 11

so its 36 too right?

Answer 12

But yah, it could not be different than the angle between that side of the tree and the same rope.

Answer 13

Yah, 36.

Answer 14

On the last one, I see a problem.

Answer 15

AB is the bisector of IK, therefore IK has been bisected. HOWEVER: We do not know if AB has been bisected or not.

Answer 16

We also know AB and IK are at right angles, perpendicular.

That is all we have.

Answer 17

Now, can you see why I say that does not mean: BK = AK ??

Answer 18

We do not know where A and B are. There is no relationship between them. So what if A was half way down that line?

Answer 19

The thing that gave it away to me is that IK has been bisected. Not anything about IAK.

Answer 20

Well, to be honest, you were close with the first answer, but had the wrong points. I think yo had the right idea, don't know, but think so. You just looked at the wrong line as being bisected.

Answer 21

Yes, that is what I have been hinting at.

Answer 22

Beacuse IK is bisected, IJ=JK. Well, any point on the perpendicular bisecting line would have that same basic property.

Answer 23

#4... point of concurrency .... oh they love their geek speak....

And you got that one right. Had to look it up myself. LOL. Normally they call it the intersection so I got a tad confused. Hehe.

Answer 24

Lol so 4 is good? What abou tthe others?

Answer 25

5 looks like a right triangle. Have anything about a special case for the right triangle and the circumcenter?

Answer 26

Im not sure o.o idk what you mean D:

Answer 27

http://www.mathopenref.com/trianglecircumcenter.html

Answer 28

Knowing what it is, I would solve it by a matrix on the perpendicular lines at the midpoints of two sides... but that special case... oh, which does work with the midpoints of the adjacent sides to the right angle. Let me find the actual point...

Answer 29

Yah, (4,5). That would be it.

Answer 30

Wow I got it right...lol

Answer 31

I was thinking about it in terms of the relationship, 2 over, 1 up. Should have just foinished the problem and told you. Hehe.

Answer 32

Lol oh well, so 4 and 5 are good. What about 6?

Answer 33

6 Inside only.

Answer 34

Thats what I though xD Can you help with more?

Answer 35

A perpendicular bisector of a side can end up outside. An ANGLE though, inside only. So you were absolutly right.

Answer 36

Sure, I am off today. So no need to run to bed this time. Hehe.

Answer 37

/poke /poke Grades are supposed to go up! Hehe.

Answer 38

Oh man, not cool...

Answer 39

Yes, I have seen that proven in Linear Algebra. the 2 to 1 ratio. Since GE is longer, it would be the 2/3 and the BG is 1/3. Since the whole is 9, 2/3 is 6 and 1/3 is 3.

Answer 40

Why do you think it is wrong. It is right! But I want to talk about the doubt for a moment and clear it up.

Answer 41

OK. Well, it is Perpendicular, and that fiast one has that word. Maybe that cast some doubt... but it does not bisect. Here is another point. Area of a triangle is 1/2 base x height. How high up you are is your altitude.

Answer 42

Oh right xD

Answer 43

Well, a quick sketch did not do it for me. Hehe.

OK, so lets work that one a tad.

Answer 44

Lol great xD

Answer 45

OK, I looked it up. Seems to be what I would expect. You need the slope of two sides. Then, you do a point slope for the line that passes through the vertex that is NOT on the line you got the slope for. Now, there is an easy one in this problem to start with.

Answer 46

Which of those lines is easiest to get a perpendicular to?