Question

Hydrogen sulfide gas is bubbled through excess
potassium hydroxide solution.
H2S + 2OH– → S2– + 2H2O

How do you get there from
H2S + KOH -> K2S + H2O ?

Answer 1

what exactly you want ???

Answer 2

H2S + KOH -> K2S + H2O

Write the balanced chemical equation excluding spectator ions.
I want to know how to get from there to this:
H2S + 2OH– → S2– + 2H2O

Answer 3

just separate the atoms from the molecules and give them charges example
H2S can be written as 2 H+ + S^-2 like that u right for all molecules

Answer 4

here, you have a double replacement reaction.
AB + CD = AD + CB

first, the side of your reaction is incorrect. you were told that:
Hydrogen sulfide gas is bubbled through excess potassium hydroxide solution, but you only put H2S + 2OH– → S2– + 2H2O
notice that you are missing potassium on the reaction side. without the aid of a miracle, it would be difficult to balance if you do not account everything in the reaction.

Answer 5

how do you get from here...
H2S + KOH -> K2S + H2O

to here...
H2S + 2OH– → S2– + 2H2O

Answer 6

like I said it is a double replacement reaction
AB + CD = AD + CB
\[H_2 = A; S=B; K=C;(OH)=D\]
\[[AD]=H_2+(OH)=H_2O\]
\[[CB]= K+S = KS\]
make sure it is balanced.
it seems that you are doing net ionization problem and solubility. this involves what dissolves during a reaction and what will be solid (known as precipitate). like chmvijay indicated add their appropriate charges and use the solubility rules.