Question

I really need help with this, thanks!
Part 1: Fill in the missing row of the truth table.
Part 2: Are the two statements logically equivalent? Why or why not?
(~p ∧ q) and (~p ∨ q)

Answer 1

Working on getting the table up....

Answer 2

p q ~ p ~p ∧ q ~p∨ q (~p ∧ q) ↔ (~p ∨ q)
T T F F T F
T F F F F T

F F T F T F

Answer 3

p q ~ p ~p ∧ q ~p∨ q (~p ∧ q) ↔ (~p ∨ q)
F T ? ? ? ?
Can u fill the ?s?. @Dramagirl88984

Answer 4

Sorry this took so long, I'm not really sure about these.
~p ~p^q ~p∨q (~p ∧ q) ↔ (~p ∨ q)
T F T T

Answer 5

After examining your tables, it appears that the tilde means NOT, the up-caret means AND and the down-caret means OR.

But what does ↔ mean??

Answer 6

bi conditional

Answer 7

q ~p ~p^q
T T ?

Answer 8

"Bi conditional"???

If this were hardware, I'd think you were speaking of a "tri-state" output. :-)

I don't think I've ever come across the term, but I see that wiki has a page, so I'll go read up on it.. :-)

Answer 9

if both p and q are true or false then p↔q will be true. if nt false.

Answer 10

p q p^q
T T T
T F F
F T F
F F F
does this help to find ~p^q? @Dramagirl88984

Answer 11

Yeah...just read that. :-)

It's basically an XNOR

Answer 12

ya:)

Answer 13

And thanks for responding, BTW!

Answer 14

welcome:)

Answer 15

@ajprincess -Yeah, I think I can do the rest on my own, thanks for your help!

Answer 16

welcome:) if u need further help pls ask:)